When the Transformer operates on 50 Hz Frequency
we will solve this using suppose values :
Let
Transformer =100kVA, R=800, L=1.2 H, f= 50 Hz
We know = XL = √(2πfL)
XL = √ ( 2 ✕ 3.145 ✕ 50 ✕ 1.2 )= 377Ω
XL = √ ( 2 ✕ 3.145 ✕ 50 ✕ 1.2 )= 377Ω
We know Impedance Z:√ (R^2+XL ^2 )
Z= √ (800^2 + 377^2)=884.380Ω
Power Factor Cos θ = R/Z
Power Factor Cos θ = 800/884.380 = 0.904588
We know the Output of the Transformer is Real Power =KVA
KVA ✕ Cos θ= 100 ✕ 0.904588 = 90.45 KW
When the Transformer operates on 60 Hz Frequency
Let
Transformer =100kVA, R=800, L=1.2 H, f= 60 Hz
We know = XL = √(2πfL)
XL = √ ( 2 ✕ 3.145 ✕ 60 ✕ 1.2 )= 452.88Ω
We know Impedance Z:√ (R^2+XL ^2 )
Z= √ (800^2 + 452.88^2)=919.2933Ω
Power Factor Cos θ = R/Z
Power Factor Cos θ = 800/919.2933 = 0.8702
We know the Output of the Transformer is Real Power =KVA
KVA ✕ Cos θ= 100 ✕ 0.8702 = 87.02 KW

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